Tuesday, October 27, 2015

H Weezy :)


Given q2 = .11


q = .33
p=.67
q2=.11
p2=.45
2pq=.44

Since I was given .11 as q2 I was able to determine the p, q, p2, and 2pq values.
After finding those values, I was also able to to determine the number of individuals
with the dominant, recessive, and heterozygous trait. Since the population was also
given, (1000) by multiplying each of the values of p2, q2, and 2pq by 1000 would give you
110 (.11) dominant, 450 (.45) recessive, and 440 (.44)heterozygous.

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